把下列各式分解因式(1)9a2 14b2(3)12a2 a

2021-04-18 07:38:57 字數 2612 閱讀 7442

1樓:匿名使用者

(1)9a2-1

4b2=(3a+1

2b)(3a-1

2b);

(3)12a

?ab+12b

=12(a2-2ab+b2)=1

2(a-b)2;

(3)a2-2ab-4+b2=(a-b)2-4=(a-b+2)(a-b-2);

(4)x(x2+1)2-4x3=x[(x2+1)2-4x2]=x(x2+1+2x)(x2+1-2x)=x(x+1)2(x-1)2;

(5)x2-7x-8=(x-8)(x+1);

(6)x(x-y)2+y(y-x)=(x-y)[x(x-y)-y]=(x-y)(x2-xy-y).

把下列各式因式分解:(1)ax2-16ay2(2)-2a3+12a2-18a(3)a2-2ab+b2-1(4)a2(x-y)-4b2(x-y)(5)

2樓:小米米米小米米

(1)ax2-16ay2=a(x+4y)(

duzhix-4y);(dao

專2)-2a3+12a2-18a=-2a(屬a2-6a+9)=-2a (a-3)2;(3)a2-2ab+b2-1=(a-b)2-1=(a-b+1)(a-b-1);(4)a2(x-y)-4b2(x-y)=(x-y)(a2-4b2)=(x-y) (a+2b)(a-2b);(5)(x+2)(x-6)+16=x2-4x+4=(x-2)2.

3樓:科比ai打鐵

(zhi1)ax2-16ay2=a(daox+4y)(內容x-4y);

(2)-2a3+12a2-18a

=-2a(a2-6a+9)

=-2a (a-3)2;

(3)a2-2ab+b2-1

=(a-b)2-1

=(a-b+1)(a-b-1);

(4)a2(x-y)-4b2(x-y)

=(x-y)(a2-4b2)

=(x-y) (a+2b)(a-2b);

(5)(x+2)(x-6)+16=x2-4x+4=(x-2)2.

把下列各式分解因式.(1)2a3b+8a2b2+8ab3(2)x3y2-4x2y+4x(3)9(a+b)2+12(a+b)+4(4)4x2-12x+9

4樓:御妹

(1)2a3b+8a2b2+8ab3

=2ab(a2+4ab+4b2)

=2ab(a+2b)2;

(2)x3y2-4x2y+4x

=x(x2y2-4xy+4)

=x(xy-2)2;

(3)9(a+b)2+12(a+b)+4

=[3(a+b)+2]2

=(3a+3b+2)2;

(4)4x2-12x+9=(2x-3)2.

5.把下列各式分解因式: (1)a2-14ab+49b2 (2)a(x+y)-(a-b)(x+y); (3)121x2-144y2; (4)3x

5樓:匿名使用者

解:(1)a2-14ab+49b2

=a2-2×7ab+(dao7b)2

=(專a-7b)2

(2)a(x+y)-(a-b)(屬x+y)=(x+y)(a-a+b)

=b(x+y);

(3)121x2-144y2;

=(11x)2-(12y)2

=(11x+12y)(11x-12y)

(4)3x4-12x2

=3x2(x2-4)

=3x2(x+2)(x-2)

6樓:匿名使用者

5.把下列各式分解因式:

(1)a2-14ab+49b2

=a²-2×a×7b+(7b﹚²

=(a-7b)²

(內2)a(x+y)-(a-b)(

容x+y)

=(x+y)[a-(a-b)]

=b(x+y)

(3)121x2-144y2

=(11x)²-(12y)²

=(11x+12y)(11x-12y)

(4)3x4-12x2

=3x²﹙x²-4)

=3x²(x+2)(x-2)

7樓:璇曉井

1(a-7b)2 (平方) 2 b(x+y) 3 ( 11x+12y)(11x-12y) 4 3x4-3x4x2=3x4x(1-2)=-3x4=-12

把下列各式分解因式(1)12a3b2-9a2b+3ab;(2)9x2-4y2;(3)x2(x-y)+(y-x);(4)(x-1)2+10(x-

8樓:神馬

(1)12a3b2-9a2b+3ab=3ab(du4a2b-3a+1);

zhi(2)9x2-4y2=(3x+2y)(dao3x-2y);

(3)x2(x-y)+(y-x)

=(x2-1)(x-y)

=(x-y)(x+1)(x-1);

(4)(x-1)2+10(x-1)+25

=(x-1+5)2

=(x-4)2.

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1 m x y n baiy x dum n zhix y dao2 2x4 32 2 回x4 16 2 x2 2 42 2 x2 4 答x2 4 2 x2 4 x 2 x 2 3 a3 a a a2 1 a a 1 a 1 4 x y 2 2 x y 1 x y 1 2 5 11 x x 1 x ...

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把下列各式因式分解 (1)ax2 16ay2(2) 2a

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